I v (which gives oxygen alkylation) competes successfully with the radical-anion sequence in the case of mnitrobenzyl~ hloride.~'J~~~ m-Nitrocumyl chloride (Va), being a tertiary chloride, would not be expected to undergo sN2 displacements,'and since the radical anion derived from m-nitrocumyl chloride is analogous to IV, elimination of chloride ion should be relatively difficult. Nonetheless, when mnitrocumyl chloride (Va) is treated with a solution ...