Abstract IndPPh 2 (1) reacts with RCH 2 Br to form the phosphonium salts [RCH 2 P (Ph) 2 Ind]+ Br−(2: R= Ph; 3: R= C 6 F 5) in high yields. Oxidation of 1 with H 2 O 2 in THF proceeds smoothly to give the phosphane oxide IndP (O) Ph 2 (4). Dehydrobromination of 2 and 3 with NaH in THF yields the corresponding indenylidenephosphoranes C 9 H 6= P (Ph) 2 CH 2 R (5: R= Ph; 6: R= C 6 F 5). Further deprotonation of 6 with excess NaH results in formation ...