Abstract Treatment of Sn (SPh) 2 with PhSH and Et3N affords a tin (II) complex, soluble in organic solvents, which is the best reducing agent for azides reported so far. Bu 2 SnH 2, although not so reactive, also shows several advantages with regard to the standard reducing agents for azides, such as its solubility in most solvents or its scarce reactivity with water.
